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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+disp('the given matrix is:')
+a=[1 0;6 -1]
+disp(a,'A=')
+disp('Since A is triangular, eigenvalues are the diagonal entries.')
+disp(a(2,2),a(1,1),'Eigenvalues are:')
+disp('for lambda=1')
+disp('A-1I=')
+b=a-eye(2,2)
+disp(b)
+disp('Hence, x1=(1/3)x2 with x2 as free variable.')
+disp('Eigenvector corresponding to lambda=1 is:')
+u1=[1;3]
+disp(u1)
+disp('for lambda=-1')
+disp('A-(-1)I=')
+b=a+eye(2,2)
+disp(b)
+disp('Hence, x1=0 with x2 as free variable.')
+disp('Eigenvector corresponding to lambda=-1 is:')
+u2=[0;1]
+disp(u2)
+disp('Thus, matrix P=')
+disp([u1 u2])
+disp('and matrix D=')
+disp([1 0;0 -1]) \ No newline at end of file