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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2528/CH11/EX11.1/Ex11_1.sce | |
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-rwxr-xr-x | 2528/CH11/EX11.1/Ex11_1.sce | 22 |
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diff --git a/2528/CH11/EX11.1/Ex11_1.sce b/2528/CH11/EX11.1/Ex11_1.sce new file mode 100755 index 000000000..647a1e2f2 --- /dev/null +++ b/2528/CH11/EX11.1/Ex11_1.sce @@ -0,0 +1,22 @@ +// Chapter 11
+// Design a low pass Butterworth filter
+// Page.No-397
+// Example11_1
+//Figure 11.13 and 11.14
+// Given
+clear;clc;
+L=1.414; //Alpha
+Ri=1; //in Ohm
+Rf=2-L;
+printf("\n The value of Rf is = %.3f Ohm\n",Rf); // Result
+Av=1+Rf/Ri;
+printf("\n The pass band gain of = %.3f \n",Av); // Result
+fc=1000; //in Hz
+W=2*%pi*fc;
+printf("\n The critical frequency is = %.0f radians per seconds\n",W); // Result
+R=1/W;
+printf("\n The Resistor required is = %.6f Ohm\n",R); // Result
+C1=2/L;
+printf("\n The capacitor1 required is = %.3f F\n",C1); // Result
+C2=L/2;
+printf("\n The capacitor2 required is = %.3f F\n",C2); // Result
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