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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 5.30
+clc;
+clear;
+close;
+format('v',6)
+// Given data
+L = 150;// in µH
+L = L * 10^-6;// in H
+// f = 1/(2*%pi*sqrt(L*C)) or C = 1/(4*%pi^2*f^2*L)
+//For f= 500 kHz
+f1 = 500;// in kHz
+f1 = f1 * 10^3;// in Hz
+C1 = 1/(4*%pi^2*f1^2*L);// in F
+//For f= 1500 kHz
+f2 = 1500;// in kHz
+f2 = f2 * 10^3;// in Hz
+C2 = 1/(4*%pi^2*f2^2*L);// in F
+C1= C1*10^12;// in pF
+C2= C2*10^12;// in pF
+disp("The required capacitor range is : "+string(C2)+" pF to "+string(C1)+" pF")
+
+// Note: The answer in the book is wrong.