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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 5.19
+clc;
+clear;
+close;
+format('v',6)
+// Given data
+dAf_byAf = 10/100;
+dAbyA = 10;
+A = 1000;
+// dAf_byAf = dAbyA*(1/(1+(A*Beta)));
+// The required feed back
+Beta = ((dAbyA/dAf_byAf)-1)/A;
+disp(Beta,"The required feed back is");
+Af = A/(1+(A*Beta));// closed loop voltage gain
+disp(Af,"The closed loop voltage gain is");