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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
commitb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch)
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+clear
+clc
+// At 400k, -rA=2.3*pA^2
+//At 500 k, -rA=2.3*pA^2
+k1=2.3;k2=2.3;T1=400;T2=500;
+//R=82.06*10^-6 m3.atm/mol.k
+R=82.06*10^-6;
+R1=8.314;//m3.pa/mol.k
+E=(log(k2/k1)*R)/(1/T1-1/T2)
+printf("\nRESULT\n")
+printf("E(J/mol)using pressure units is %f",E)
+//pA=CA*RT
+//-rA=2.3(RT)^2*CA^2
+k1=2.3*(R*T1)^2
+k2=2.3*(R*T2)^2
+E=(log(k2/k1)*R1)/(1/T1-1/T2)
+printf("\nE(J/mol)using concentration units is %f",E)
+