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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear
+clc
+t=[0;2;4;6];
+XA=[0.75;0.64;0.52;0.39];
+t1=4000;//kg.s/m3
+density_s=1500;//kg/m3
+De=5*10^-10;
+d=2.4*10^-3;
+//Assuming -rA=kCA*a,-da/dt=kd*a
+//For this rate a plot of ln(CAo/CA-1)vs t should give a straight line
+for i=1:4
+ y(i)=log((1/(1-XA(i)))-1);
+end
+plot(y,t)
+xlabel('t')
+ylabel('ln(CAo/CA-1)')
+//Guessing No Intrusion of Diffusional Resistance
+//ln(CAo/CA-1)=ln(k*t1)-kd*t
+coeff =regress(t,y);
+kd=coeff(2);
+k=exp(coeff(1))/t1;
+L=d/6;
+Mt=L*sqrt(k*density_s/De);
+//Assuming Runs were made in regime of strong resistance to pore diffusion
+k1=((exp(coeff(1)))^2)*(L^2)*density_s/(t1*t1*De);
+kd1=-2*coeff(2);
+Mt=L*sqrt(k1*density_s/De);
+printf("\n Rate equation(mol/kg.s) in diffusion free regime with deactivation is %f ",k1)
+printf("CA*a with \n -da/dt(hr-1) is %f",kd1)
+printf("a")
+//In strong pore diffusion
+k2=k1*sqrt(De/(k1*density_s));
+printf("\n Rate equation(mol/kg.s) in strong pore diffusion resistance regime with deactivation is %f ",k2)
+printf("CA*a^0.5/L with \n -da/dt(hr-1) is %f",kd1)
+printf("a")
+
+
+
+