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+clear ;

+clc;

+// Example 5.9

+printf('Example 5.9\n\n');

+printf('Page No. 122\n\n');

+

+// given

+P1 = 15;// Pressure at state 1 in bar

+P2 = 1.5;// Pressure at state 2 in bar

+T1 = 198;// in degree celcius

+

+// as the process is adiabatic; => Q = 0; => ehthalpy at state1 = enthalpy at state 2

+h_1 = 2789*10^3;// specific enthalpy at state 1 in J/kg

+h_2 = h_1;//specific enthalpy at state 2 in J/kg

+

+T3 = 150;// in degree celcius

+T4 = 200;// in degree celcius

+h_3 = 2773*10^3;// specific enthalpy at state 3 in J/kg

+h_4 = 2873*10^3;// specific enthalpy at state 4 in J/kg

+

+// Assuming a liner realtionship between temperature and enthalpy for the temperature range 150-200 degree celcius

+h = ((h_4 - h_3)/(T4 - T3));// specific enthalpy per degree celcius in J/kg-degC

+t = ((h_2 - h_3)/h);// in degree celcius

+T2 = T3 + t;// in degree celcius

+printf('the temperature of the final superheated steam at 1.5 bar is %.0f deg C',T2)

+

+