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authorpriyanka2015-06-24 15:03:17 +0530
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+clear ;
+clc;
+// Example 5.11
+printf('Example 5.11\n\n');
+printf('Page No. 130\n\n');
+
+// given
+T1 = 180;// in degree celcius
+T2 = 350;// in degree celcius
+m = 0.5;// Mass flow rate in kg/s
+
+
+//from steam table
+hL_180 = 302*10^3;// Specific enthalpy at 180 degree celcius in J/kg
+hL_350 = 690*10^3;// Specific enthalpy at 350 degree celcius in J/kg
+
+Q = m*(hL_350 - hL_180);// in W
+printf('The required heat is %.0f W',Q)