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+clear ;
+clc;
+// Example 1.4
+printf('Example 1.4\n\n');
+printf('Page No. 10\n\n');
+// Solution
+
+// Given
+mc= 1.5*10^3;// coke consumption in tonnes
+mg= 18*10^3;// gas consumption in therms
+me= 1*10^9;// electricity consumption in Wh
+Cc1= 72;// cost of coke in Pound per tonne
+Cg1= 0.20;// cost of gas in Pound per therm
+Ce1= 2.25*10^-5 ;// cost of electricity in Pound per Wh
+Cc= mc*Cc1;//in Pound
+Cg= mg*Cg1;//in Pound
+Ce= me*Ce1;//in Pound
+Ct= Cc+Cg+Ce;//in Pound
+printf('cost of coke consumption is %.0f Pound \n',Cc)
+printf('cost of gas consumption is %.0f Pound \n',Cg)
+printf('cost of electricity consumption is %.0f Pound \n',Ce)
+printf('total cost is %3.0f Pound \n',Ct)