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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2465/CH8/EX8.4 | |
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initial commit / add all books
Diffstat (limited to '2465/CH8/EX8.4')
-rw-r--r-- | 2465/CH8/EX8.4/Ex8_4.sce | 24 |
1 files changed, 24 insertions, 0 deletions
diff --git a/2465/CH8/EX8.4/Ex8_4.sce b/2465/CH8/EX8.4/Ex8_4.sce new file mode 100644 index 000000000..a9d10cf1d --- /dev/null +++ b/2465/CH8/EX8.4/Ex8_4.sce @@ -0,0 +1,24 @@ +//Chapter-8,Example 4,Page 196
+clc();
+close();
+
+alpha1=0.02
+
+Ka=1.8*10^-5
+
+//at equilibrium..
+//[CH3COOH] = C1* (1-alpha1)
+//[H+] = C1* alpha1
+//[CH3COO-] = C1* alpha1
+// Ka =[H+] * [CH3COO-]/[CH3COOH]
+// Ka = C1* alpha1*C1* alpha1/(C1 (1-alpha1))
+
+C1=Ka*(1-alpha1)/alpha1^2
+
+printf('the molar concentration of CH3COOH is C = %.4f molar',C1)
+
+C2=0.01
+
+alpha2= sqrt(Ka/C2)
+
+printf('\n alpha = %.4f ',alpha2)
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