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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Chapter-3,Example 17,Page 61
+clc;
+close;
+
+m_Ca = 39.975 //atomic mass of Calcium in a.m.u.
+
+a_no= 20 //atomic number of calcium
+
+m_proton = 1.0078 //mass of proton
+
+m_neutron = 1.0086 //mass of neutron\
+
+delta_m=a_no*(m_neutron + m_proton)- m_Ca //mass defect
+
+energy= delta_m*931/40 //binding energy per nucleon
+
+printf('binding energy per nucleon is %.3f MeV',energy)
+