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+//chapter3
+//example3.3
+//page49
+
+// for constant Ec=-1.5
+Eb1=100 // V
+Eb2=150 // V
+Ib1=7.5d-3 // A
+Ib2=12d-3 // A
+
+Eb_diff=Eb2-Eb1
+Ib_diff=Ib2-Ib1
+
+rp=Eb_diff/Ib_diff
+rp_kilo_ohm=rp/10^3 //kilo ohm
+
+printf("plate resistance = %.3f ohm or %.3f kilo ohm \n",rp,rp_kilo_ohm)
+
+// for constant Eb=150
+Ib1=5d-3 // A
+Ib2=12d-3 // A
+Ec1=-3 // V
+Ec2=-1.5 // v
+
+Ib_diff=Ib2-Ib1
+Ec_diff=Ec2-Ec1
+
+gm=Ib_diff/Ec_diff
+gm_micro_mho=gm*10^6 //micro mho
+printf("mutual conductance=%.3f mho or %.3f micro mho \n",gm,gm_micro_mho)
+
+mu=rp*gm
+printf("amplification factor = %.3f",mu)
+
+//in book the answer of amplification factor i.e. 51.852 is rounded off to 52