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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /2459/CH19/EX19.2/Ex19_2.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '2459/CH19/EX19.2/Ex19_2.sce')
-rw-r--r-- | 2459/CH19/EX19.2/Ex19_2.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/2459/CH19/EX19.2/Ex19_2.sce b/2459/CH19/EX19.2/Ex19_2.sce new file mode 100644 index 000000000..17a5275ad --- /dev/null +++ b/2459/CH19/EX19.2/Ex19_2.sce @@ -0,0 +1,17 @@ +//chapter19
+//example19.2
+//page416
+
+// figure is given in book for understanding purpose only.It is not required for solving the example as maximum and minimum peak voltages are given in the problem statement itself.
+
+Vmax_pp=16 // mV
+Vmin_pp=4 // mV
+
+Vmax=Vmax_pp/2
+Vmin=Vmin_pp/2
+
+m=(Vmax-Vmin)/(Vmax+Vmin)
+
+printf("modulation factor = %.3f \n",m)
+
+
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