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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//chapter12
+//example12.9
+//page245
+
+V_CC=12 // V
+gain_beta1=100
+gain_beta2=50
+V_BE=0.3 // V
+V_CE=8 // V
+I_C=1 // mA
+
+// here V_CC=V_CE+I_C*R_C so we get
+R_C=(V_CC-V_CE)/I_C
+
+I_B=I_C/gain_beta1
+
+// we know that R_B=(V_CC-V_BE-gain_beta1*R_C*I_B)/I_B so
+R_B=(V_CC-V_BE-gain_beta1*R_C*I_B)/I_B
+
+
+// for gain_beta=50 i.e. gain_beta2
+
+// we know that R_B=(V_CC-V_BE-gain_beta2*R_C*I_B)/I_B so we get
+I_B2=(V_CC-V_BE)/(R_B+gain_beta2*R_C)
+
+I_C2=gain_beta2*I_B2
+
+V_CE2=V_CC-I_C2*R_C
+
+printf("for beta=100,required base resistance = %.3f kilo ohm \n",R_B)
+printf("for beta=50,new operating point is %.3f V, %.3f mA \n",V_CE2,I_C2)