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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//chapter11
+//example11.14
+//page218
+
+Vcc=12.5 // V
+Rc=2.5 // kilo ohm
+
+// we know that Vce=Vcc-Ic*Rc
+// when Ic=0, Vce=Vcc i.e. 12.5V
+// when Vce=0, Ic=Vcc/Rc i.e.5mA
+
+// so equation of load line becomes Ic=-0.4*Vce+5
+x=linspace(0,12.5,5)
+y=-0.4*x+5
+clf()
+xtitle("dc load line","Vce(volts)","Ic(mA)")
+plot2d(x,y,style=3,rect=[0,0,13,6])