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+//Example No. 4_03

+//Pg No. 64

+clear ; close ; clc ;

+

+a = 0.1

+b = 0.4

+for i = 1:8

+    afrac(i) = floor(a*2)

+    a = a*2 - floor(a*2)

+    bfrac(i) = floor(b*2)

+    b = b*2 - floor(b*2)

+end

+afrac_s = '0' + '.' + strcat(string(afrac)) //string form binary equivalent of a i.e 0.1

+bfrac_s = '0' + '.' + strcat(string(bfrac))

+mprintf('\n 0.1_10 = %s \n 0.4_10 = %s \n ', afrac_s , bfrac_s)

+for j = 8:-1:1

+    summ(j) = afrac(j) + bfrac(j)

+    if summ(j) > 1 then

+        summ(j) = summ(j)-2

+        afrac(j-1) = afrac(j-1) + 1

+    end

+end

+summ_dec = 0

+for k = 8:-1:1

+    summ_dec = summ_dec + summ(k)

+    summ_dec = summ_dec*1/2 

+end

+disp(summ_dec,'sum =')

+disp('Note : The answer should be 0.5, but it is not so.This is due to the error in conversion from decimal to binary form.')
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