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+//scilab 5.4.1

+clear;

+clc;

+printf("\t\t\tProblem Number 7.3\n\n\n");

+// Chapter 7 : Mixtures Of Ideal Gases

+// Problem 7.3  (page no. 323) 

+// Solution

+

+//Ten pounds of air,1 lb of carbon dioxide,and 5 lb of nitrogen are mixed at constant temperature until the mixture pressure is constant

+nair=10/29; //no of moles of air=ratio of mass and molecular weight //10 lb of nitrogen per pound //molecular weight of air=29

+printf("The moles of air is %f mole/lbm of mixture\n",nair);

+nCO2=1/44; //no of moles of carbon dioxide=ratio of mass and molecular weight //1 lb of per pound //molecular weight of CO2=44

+printf("The moles of carbon dioxide is %f mole/lbm of mixture\n",nCO2);

+nN2=5/28; //no of moles of nitrogen=ratio of mass and molecular weight //5 lb of nitrogen per pound //molecular weight of N2=28

+printf("The moles of nitrogen is %f mole/lbm of mixture\n",nN2);

+nm=nair+nCO2+nN2; //Unit:Mole/lbm //number of moles of gas mixture is sum of the moles of its constituent gases

+printf("The total number of moles is %f mole/lbm\n\n",nm); 

+

+xair=nair/nm //mole fraction of air=ratio of no of moles of air and total moles in mixture

+xCO2=nCO2/nm; //mole fraction of carbon dioxide=ratio of no of moles of carbon dioxide and total moles in mixture

+xN2=nN2/nm; //mole fraction of nitrogen=ratio of no of moles of oxygen and total moles in mixture

+printf("The mole fraction of air is %f \n",xair);

+printf("The mole fraction of carbon dioxide is %f\n",xCO2)

+printf("The mole fraction of nitrogen is %f\n\n",xN2);

+

+//final pressure of is 100 psia

+pair=xair*100; //the partial pressure of air= final pressure * the mole fraction of air //psia

+printf("The partial pressure of air is %f psia\n",pair);

+pCO2=xCO2*100; //the partial pressure of carbon dioxide= final pressure * the mole fraction of CO2 //psia

+printf("The partial pressure of carbon dioxide is %f psia\n",pCO2);

+pN2=xN2*100; //the partial pressure of nitrogen=final pressure * the mole fraction of nitrogen //psia

+printf("The partial pressure of nitrogen is %f psia\n\n",pN2);

+

+//the molecular weight of mixture=sum of products of mole fraction of each gas component

+MWm=(xair*29) + (xCO2*44) + (xN2*28); //The molecular weight of air 

+printf("The molecular weight of air is %f\n\n",MWm);

+

+Rm=1545/MWm; //the gas constant of air

+printf("The gas constant of air is %f\n\n",Rm);