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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2417/CH6/EX6.12 | |
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initial commit / add all books
Diffstat (limited to '2417/CH6/EX6.12')
-rwxr-xr-x | 2417/CH6/EX6.12/Ex6_12.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/2417/CH6/EX6.12/Ex6_12.sce b/2417/CH6/EX6.12/Ex6_12.sce new file mode 100755 index 000000000..076503ae1 --- /dev/null +++ b/2417/CH6/EX6.12/Ex6_12.sce @@ -0,0 +1,14 @@ +clear;
+clc;
+printf("\t\t\tProblem Number 6.12\n\n\n");
+// Chapter 6: The Ideal Gas
+// Problem 6.12 (page no. 255)
+// Solution
+
+//The molecular weight of oxygen is 32.Therefore,
+R=1545/32; //Unit:ft*lbf/lbm*R //constant of proportionality
+J=778; //conversion factor
+cp=0.24; //Unit:Btu/lbm*R //specific heat at constant pressure
+//cp-cv=R/J
+cv=cp-(R/J); //specific heat at constant volume //unit:Btu/lbm*R
+printf("Specific heat at constant volume is %f Btu/lbm*R\n",cv);
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