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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2417/CH5/EX5.16 | |
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initial commit / add all books
Diffstat (limited to '2417/CH5/EX5.16')
-rwxr-xr-x | 2417/CH5/EX5.16/Ex5_16.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/2417/CH5/EX5.16/Ex5_16.sce b/2417/CH5/EX5.16/Ex5_16.sce new file mode 100755 index 000000000..8e1632008 --- /dev/null +++ b/2417/CH5/EX5.16/Ex5_16.sce @@ -0,0 +1,21 @@ +//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 5.16\n\n\n");
+// Chapter 5 : Properties Of Liquids And Gases
+// Problem 5.16 (page no. 202)
+// Solution
+
+//It is necessary to ontain the saturation values corresponding to 300 F.This is done by reading Table A.1 in Appendix 3,which gives
+pf=66.98; //psia //pressure
+vf=0.017448; //ft^3/lbm //specific volume
+hf=269.73; //Btu/lbm //enthaply
+//Now,
+p=1000; //psia //pressure
+J=778; //Conversion factor //ft*lbf/Btu
+//From eq.5.5,
+h=hf+((p-pf)*vf*144)/J; //1ft^2=144 in^2 //The enthalpy of subcooled water //Btu/lbm
+printf("The enthalpy of subcooled water is %f Btu/lbm\n",h);
+//The difference between this value and the value found in problem 5.15,expressed as a percentage is
+percentoferror=(h-271.46)/271.46;
+printf("Percent of error is %f\n",percentoferror*100);
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