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+clear;

+clc;

+printf("\t\t\tProblem Number 3.21\n\n\n");

+// Chapter 3 : The First Law Of Thermodynamics

+// Problem 3.21 (page no. 125) 

+// Solution

+

+m=400; //Unit:LBm/min //mass of lubricating oil

+Cp=0.85; //Unit:Btu/LBm*R //Specific heat of the oil

+T1=215; //Temperature when hot oil is entering //Unit:Fahrenheit

+T2=125; //Temperature when hot oil is leaving //Unit:Fahrenheit

+DeltaT=T2-T1; //Unit:Fahrenheit  //change in temperature

+Qoil=m*Cp*DeltaT; //Heat out of oil //Btu/min

+printf("Heat out of oil is %f Btu/min (Out of oil)\n",Qoil);

+//Heat out of oil is the heat into the water

+//Mw=Water flow rate

+//M*Cpw*DeltaTw=Qoil

+Cpw=1.0; //Unit:Btu/LBm*R //Specific heat of the water

+T3=60; //Temperature when water is entering //Unit:Fahrenheit

+T4=90; //Temperature when water is leaving //Unit:Fahrenheit

+DeltaTw=T4-T3; //Unit:Fahrenheit //change in temperature

+Mw=Qoil/(Cpw*DeltaTw); //The Required water flow rate  //Unit;lbm/Min

+printf("The Required water flow rate is %f lbm/Min\n",abs(Mw));