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+//scilab 5.4.1

+clear;

+clc;

+printf("\t\t\tProblem Number 11.26\n\n\n");

+// Chapter 11 : Heat Transfer

+// Problem 11.26  (page no. 603) 

+// Solution

+

+//From the table 11.7,

+//For the oil side,a resistance(fouling factor) of 0.005 (hr*F*ft^2)/Btu can be used

+//and for the water side,a fouling factor of 0.001 (hr*F*ft^2)/Btu can be used

+//From problem 11.25,

+U=40;//The coefficient of heat transfer of the unit //Unit:Btu/(hr*ft^2*F)

+//therefore,

+Roil=0.005; //unit:(hr*ft^2*F)/Btu //resistance at oil side

+Rwater=0.001; //unit:(hr*ft^2*F)/Btu //resistance for water side

+Rcleanunit=inv(U); //unit:(hr*ft^2*F)/Btu //resistance at clean unit

+Roverall=Roil+Rwater+Rcleanunit; //unit:(hr*ft^2*F)/Btu //overall resistance

+Uoverall=inv(Roverall); //Unit:Btu/(hr*ft^2*F) //The overall coefficient of heat transfer of the unit

+//Because all the parameters are the same,the surface area required will vary inversely as U

+A=569*(U/Uoverall); //A=569 ft^2 in the problem 11.25 //unit:ft^2  //The outside surface area

+printf("The outside surface area required is %f ft^2",A);