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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+printf("\t\t\tProblem Number 11.1\n\n\n");
+// Chapter 11: Heat Transfer
+// Problem 11.1 (page no. 553)
+// Solution
+
+
+deltaX=6/12; //6 inch = 6/12 feet //deltaX=length //unit:feet
+k=0.40; //Unit:Btu/(hr*ft*F) //k=proportionality constant //k=thermal conductivity //From the table
+T1=150; //temperature maintained at one face //fahrenheit
+T2=80; //tempetature maintained at other face //fahrenheit
+deltaT=T2-T1; //fahrenheit //Change in temperature
+Q=(-k*deltaT)/deltaX; //Heat transfer per square foot of wall //Unit:Btu/hr*ft^2
+printf("Heat transfer per square foot of wall is %f Btu/hr*ft^2",Q);