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authorpriyanka2015-06-24 15:03:17 +0530
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-rwxr-xr-x24/CH27/EX27.2/Example27_2.sce16
-rwxr-xr-x24/CH27/EX27.2/Example27_2_result.txt5
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diff --git a/24/CH27/EX27.2/Example27_2.sce b/24/CH27/EX27.2/Example27_2.sce
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+//Given that
+R = 2*10^-3 //in meter
+J = 2*10^5 //in A/m^2
+
+//Sample Problem 27-2a
+printf("**Sample Problem 27-2a**\n")
+//As current density is uniform
+A = %pi*(R^2 - (R/2)^2)
+I = J*A
+printf("The current flowing through the outer portion is %fA\n", I)
+
+//Sample Problem 27-2b
+printf("\n**Sample Problem 27-2b**\n")
+a = 3*10^11 //in SI unit
+Iv = integrate('a*r^2*2*%pi*r', 'r', R/2, R)
+printf("Now the current will be %fA", Iv) \ No newline at end of file
diff --git a/24/CH27/EX27.2/Example27_2_result.txt b/24/CH27/EX27.2/Example27_2_result.txt
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+**Sample Problem 27-2a**
+The current flowing through the outer portion is 1.884956A
+
+**Sample Problem 27-2b**
+Now the current will be 7.068583A \ No newline at end of file