initial commit / add all books

16 files changed, 124 insertions, 0 deletions

diff --git a/24/CH15/EX15.1/Example15_1.sce b/24/CH15/EX15.1/Example15_1.sce
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+//Given that
+l = 3.5  //in meter
+b = 4.2  //in meter
+h = 2.4  //in meter
+g = 9.8  //in m/s^2
+
+//Sample Problem 15-1a
+printf("**Sample Problem 15-1a**\n")
+P = 1.0*1.01*10^5  //in N/m^2
+density_air = 1.21  //in kg/m^3 at 1atm pressure
+V = l*b*h  //Volume of the air
+W = density_air*V*g  //Weight of the air
+printf("The weight of the air in the room is equal to %fkg\n", W)
+
+//Sample Problem 15-1b
+printf("\n**Sample Problem 15-1b**\n")
+A = l*b
+F = P*A
+printf("The magnitude of atmosphere force on the floor of the room is %eN\n", F)
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diff --git a/24/CH15/EX15.1/Example15_1_result.txt b/24/CH15/EX15.1/Example15_1_result.txt
new file mode 100755
index 000000000..a3abf798a
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+**Sample Problem 15-1a**

+The weight of the air in the room is equal to 418.350240kg

+

+**Sample Problem 15-1b**

+The magnitude of atmosphere force on the floor of the 
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diff --git a/24/CH15/EX15.2/Example15_2.sce b/24/CH15/EX15.2/Example15_2.sce
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index 000000000..afa11509d
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+++ b/24/CH15/EX15.2/Example15_2.sce
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+//Given that

+deltaP = 9.3*10^3  //in N/m^2

+density_water = 998  //in kg/m^3

+g = 9.8  //in m/s^2

+

+//Sample Problem 15-2

+printf("**Sample Problem 15-2**\n")

+//deltaP = density_water*g*L

+//therefore

+L = deltaP/(density_water*g)

+printf("The diver started at a depth of %fm", L)
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diff --git a/24/CH15/EX15.2/Example15_2_result.txt b/24/CH15/EX15.2/Example15_2_result.txt
new file mode 100755
index 000000000..899a74737
--- /dev/null
+++ b/24/CH15/EX15.2/Example15_2_result.txt
@@ -0,0 +1,2 @@
+*Sample Problem 15-2**

+The diver started at a depth of 0.950881m
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diff --git a/24/CH15/EX15.3/Example15_3.sce b/24/CH15/EX15.3/Example15_3.sce
new file mode 100755
index 000000000..d133f9fbd
--- /dev/null
+++ b/24/CH15/EX15.3/Example15_3.sce
@@ -0,0 +1,10 @@
+//Given that

+density_water = 998  //in kg/m^3

+l = 135*10^-3  //in meter

+d = 12.3*10^-3  //in meter

+g = 9.8  //in m/s^2

+

+//Sample Problem 15-3

+printf("**Sample Problem 15-3**\n")

+d_oil = density_water*g*l/(g*(l+d))  //pressure at same height should be same

+printf("The density of the oil is %fkg/m^3", d_oil)
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diff --git a/24/CH15/EX15.3/Example15_3_result.txt b/24/CH15/EX15.3/Example15_3_result.txt
new file mode 100755
index 000000000..11a085145
--- /dev/null
+++ b/24/CH15/EX15.3/Example15_3_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-3**

+The density of the oil is 914.663951kg/m^3 
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diff --git a/24/CH15/EX15.4/Example15_4.sce b/24/CH15/EX15.4/Example15_4.sce
new file mode 100755
index 000000000..96a187999
--- /dev/null
+++ b/24/CH15/EX15.4/Example15_4.sce
@@ -0,0 +1,11 @@
+//Given that

+density_ice = 917  //in kg/m^3

+density_seawater = 1024  //in kg/m^3

+

+//Sample Problem 15-4

+printf("**Sample Problem 15-4**\n")

+//Using archimedies principle

+//density_seawater*Vs*g = density_ice*Vt*g

+//fractoin of non-visible part 'f' is

+f = density_ice/density_seawater  //Vs/Vt

+printf("The fraction of the visible part is equal to %f", (1-f))
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diff --git a/24/CH15/EX15.4/Example15_4_result.txt b/24/CH15/EX15.4/Example15_4_result.txt
new file mode 100755
index 000000000..e306c15cb
--- /dev/null
+++ b/24/CH15/EX15.4/Example15_4_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-4**

+The fraction of the visible part is equal to 0.104492 
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diff --git a/24/CH15/EX15.5/Example15_5.sce b/24/CH15/EX15.5/Example15_5.sce
new file mode 100755
index 000000000..dc1eacb3e
--- /dev/null
+++ b/24/CH15/EX15.5/Example15_5.sce
@@ -0,0 +1,12 @@
+//Given that

+R = 12.0  //in meter

+m = 196  //in kg

+density_He = 0.160  //in kg/m^3

+density_air = 1.25  //in kg/m^3

+g = 9.8  //in m/s^2

+

+//Sample Problem 15-5

+printf("**Sample Problem 15-5**\n")

+Vb = 4/3*%pi*R^3

+PayLoad = (density_air*Vb*g - (density_He*Vb*g + m*g))/g

+printf("The maximum mass attached can be %fkg", PayLoad)
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diff --git a/24/CH15/EX15.5/Example15_5_result.txt b/24/CH15/EX15.5/Example15_5_result.txt
new file mode 100755
index 000000000..2236b75c1
--- /dev/null
+++ b/24/CH15/EX15.5/Example15_5_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-5**

+The maximum mass attached can be 7693.670127kg 
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diff --git a/24/CH15/EX15.6/Example15_6.sce b/24/CH15/EX15.6/Example15_6.sce
new file mode 100755
index 000000000..0cae039ea
--- /dev/null
+++ b/24/CH15/EX15.6/Example15_6.sce
@@ -0,0 +1,10 @@
+//Given that

+Ao = 3*10^-4  //in m^2

+Vo = 30*10^-2  //in m/s

+A = 3*10^-7*10^-4  //in m^2

+V = 0.05*10^-2  //in m/s

+

+//Sample Problem 15-6

+printf("**Sample Problem 15-6**\n")

+n = (Ao*Vo)/(A*V)

+printf("Number of capillaries a person should have %e", n)
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diff --git a/24/CH15/EX15.6/Example15_6_result.txt b/24/CH15/EX15.6/Example15_6_result.txt
new file mode 100755
index 000000000..658639afa
--- /dev/null
+++ b/24/CH15/EX15.6/Example15_6_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-6**

+Number of capillaries a person should have 6.000000e+009 
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diff --git a/24/CH15/EX15.7/Example15_7.sce b/24/CH15/EX15.7/Example15_7.sce
new file mode 100755
index 000000000..718263188
--- /dev/null
+++ b/24/CH15/EX15.7/Example15_7.sce
@@ -0,0 +1,16 @@
+exec('Bernauli.sci', -1)

+

+//Given that

+Ao = 1.2*10^-4  //in m^2

+A = 0.35*10^-4  //in m^2

+h = 45*10^-3  //in m

+density_water = 998  //in kg/m^3

+

+//Sample Problem 15-7

+printf("**Sample Problem 15-7\n")

+A = [A, Ao]

+deltaP = 0  //in N/m^2

+density = density_water

+V = fsolve([0,0], Bernauli)

+FlowRate = A(1)*V(1)

+printf("The volume flow rate from the tap is equal to %fcm^3/s", FlowRate*10^6)
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diff --git a/24/CH15/EX15.7/Example15_7_result.txt b/24/CH15/EX15.7/Example15_7_result.txt
new file mode 100755
index 000000000..a455e8022
--- /dev/null
+++ b/24/CH15/EX15.7/Example15_7_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-7

+The volume flow rate from the tap is equal to 34.364361cm^3/s 
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diff --git a/24/CH15/EX15.8/Example15_8.sce b/24/CH15/EX15.8/Example15_8.sce
new file mode 100755
index 000000000..92a6b3520
--- /dev/null
+++ b/24/CH15/EX15.8/Example15_8.sce
@@ -0,0 +1,16 @@
+exec('Bernauli.sci', -1)

+

+//Given that

+density_Ethanol = 791  //in kg/m^3

+A1 = 1.20*10^-3  //in m^2

+A2 = A1/2

+//Pressure in narrower section is lesser

+deltaP = -4120  //in N/m^2

+

+//Sample Problem 15-8

+printf("**Sample Problem 15-8**\n")

+A = [A1, A2]

+density = density_Ethanol

+h = 0

+V = fsolve([0, 1], Bernauli)

+printf("The volume flow rate is %e m^3/s", abs(A1*V(1)))
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diff --git a/24/CH15/EX15.8/Example15_8_result.txt b/24/CH15/EX15.8/Example15_8_result.txt
new file mode 100755
index 000000000..6cb047269
--- /dev/null
+++ b/24/CH15/EX15.8/Example15_8_result.txt
@@ -0,0 +1,2 @@
+**Sample Problem 15-8**

+The volume flow rate is 2.236125e-003 m^3/s
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