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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 6.3
+clc;
+clear;
+close;
+format('v',5)
+// Given data
+I_Don = 10;// in mA
+I_Don = I_Don * 10^-3;// in A
+V_GS = -12;// in V
+V_GSt = -3;// in V
+//From I_Don = Kn*((V_GS-V_GSt)^2);
+Kn = I_Don/((V_GS-V_GSt)^2);// in A/V
+Kn= Kn* 10^3;// in mA/V
+V_GS = -6;// in V
+I_D = Kn*((V_GS-V_GSt)^2);// in mA
+disp(I_D,"The drain current in mA is");