initial commit / add all books

7 files changed, 100 insertions, 0 deletions

diff --git a/2345/CH4/EX4.1/Ex4_1.sce b/2345/CH4/EX4.1/Ex4_1.sce
new file mode 100755
index 000000000..a1fb9414d
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+++ b/2345/CH4/EX4.1/Ex4_1.sce
@@ -0,0 +1,14 @@
+//Finding capacitance
+//Example 4.1(pg 110)
+clc
+clear
+// Let C1 and C2 be unknown capacities
+//C1+C2=0.16
+//(C1*C2)/(C1 + C2)=0.03
+// from the above 2 equations we get the following polynomial
+s=poly(0,"s");
+p=s^2 -0.16*s +0.0048
+[c1]=roots(p)
+c2=0.16-c1
+printf('Thus the capacitance of condensers is  %3.2f microF \n ',c1)
+
diff --git a/2345/CH4/EX4.2/Ex4_2.sce b/2345/CH4/EX4.2/Ex4_2.sce
new file mode 100755
index 000000000..eb3f0efe0
--- /dev/null
+++ b/2345/CH4/EX4.2/Ex4_2.sce
@@ -0,0 +1,13 @@
+//Finding capacitance

+//Example 4.2(pg 110)

+clc

+clear

+n=9;

+Ko=8.854*10^-12;

+K=5;

+A=12*10^-4;

+d=2*10^-4;

+

+C=(n-1)*Ko*K*A/d

+printf('Thus the capacitance is %e F',C);

+//The Answer in the Textbook has a calculation error, hence it doesn't match the answer here.

diff --git a/2345/CH4/EX4.3/Ex4_3.sce b/2345/CH4/EX4.3/Ex4_3.sce
new file mode 100755
index 000000000..217d9fc51
--- /dev/null
+++ b/2345/CH4/EX4.3/Ex4_3.sce
@@ -0,0 +1,13 @@
+//Finding heat

+//Example 4.3(pg 110)

+clc

+clear

+C=10^-6

+V=10000

+//here C is capacitance and V voltage

+E=1/2*C*V^2

+//E is the energy stored in the capacitor

+// when the capacitor is discharged all this energy is dissipated as heat in the wire

+H=E/4.2

+//H is heat produced in calories since 4.2 Joules=1 calorie

+printf('Thus the heat produced is %3.4f calories',H)

diff --git a/2345/CH4/EX4.4/Ex4_4.sce b/2345/CH4/EX4.4/Ex4_4.sce
new file mode 100755
index 000000000..91148253a
--- /dev/null
+++ b/2345/CH4/EX4.4/Ex4_4.sce
@@ -0,0 +1,16 @@
+//Finding electric flux density

+//Example 4.4(pg 111)

+clc

+clear

+

+A=0.02;//surface area of plates in meter square

+d=0.001;//distance between the plates in meter

+C=4.5*10^-10;//capacitance of the capacitor in farad

+//for paralel plate condenser C=KoKA/d

+Ko=8.854*10^-12;

+//dielectric constant K is given by

+K=(C*d)/(Ko*A)

+V=15000;//volatage in volts

+Q=C*V// charge on condenser in columb

+D=Q/A// electric flux density in columb per meter square

+printf('Thus the electric flux density is %e C/(m^2)',D)

diff --git a/2345/CH4/EX4.5/Ex4_5.sce b/2345/CH4/EX4.5/Ex4_5.sce
new file mode 100755
index 000000000..7903a3ffb
--- /dev/null
+++ b/2345/CH4/EX4.5/Ex4_5.sce
@@ -0,0 +1,19 @@
+//Finding relative permittivity

+//Example 4.5(pg 111)

+clc

+clear

+//before inserting the second sheet

+d=0.003;//distacne between plates in m^2

+K1=6;// relative permittivity of air

+Ko=8.854*10^-12;

+// capacitance C1=Ko*K1*A/d in Farad

+//after inserting the second sheet

+d1=0.003;//thickness of first sheet in meter

+d2=0.005;//thickness of second sheet in meter

+//K2 is unknown

+//C2=Ko*A/(d1/K1 + d2/K2)

+// but given that C2=(1/3)*C1

+//from equations 1,2,3

+K2= (d2*K1)/(3*d-d1)

+// since Ko*A/(d1/K1 + d2/K2)=Ko*K1*A/3*d

+printf('Thus K2 is %3.4f',K2)

diff --git a/2345/CH4/EX4.6/Ex4_6.sce b/2345/CH4/EX4.6/Ex4_6.sce
new file mode 100755
index 000000000..80fa89917
--- /dev/null
+++ b/2345/CH4/EX4.6/Ex4_6.sce
@@ -0,0 +1,14 @@
+//Finding force

+//Example 4.6(pg 113)

+clc

+clear

+q1=1;// in coulomb

+q2=1;// in coulomb

+Eo=8.854*10^-12;// in Farad per meter

+Er=1;

+d=1// in meter

+pi=3.14;

+// F is the force between 2 charges in NEWTONS

+F=(q1*q2)/(4*pi*Eo*Er*d^2)

+

+printf('Thus the force between 2 charges is %e',F)

diff --git a/2345/CH4/EX4.7/Ex4_7.sce b/2345/CH4/EX4.7/Ex4_7.sce
new file mode 100755
index 000000000..fbba474bd
--- /dev/null
+++ b/2345/CH4/EX4.7/Ex4_7.sce
@@ -0,0 +1,11 @@
+//Finding charge

+//Example 4.7(pg 114)

+clc

+clear

+//q1=q2=q

+pi=3.14;

+d=0.2;// in meters

+K=9*10^9;// here K=1/4*pi*Eo*Er constant

+F=9.81*10^-1;// in newtons or 10^-1 kgm

+q=sqrt((F*(d^2))/K)

+printf('Thus charge is %e in coulomb',q)