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+//Finding current,voltage and power

+//Example 15.34(pg. 414)

+clc

+clear

+v=50*20*2//Volume of board to be heated in cm^3

+Mw=0.56//weight of wood in gm/cm^3

+m=Mw*v/1000//mass of wood in kgm

+S=0.35//specific heat of wood

+t=15/60//time in hrs

+f=30*(10^6)//frequency in cycles/sec

+t2=150,t1=30//temp in degreeC

+H=m*S*(t2-t1)//heat required to raise the temp in kcal

+Hw=H*1000/860//heat required in kW

+P=Hw/t//power required in Watts

+e=0.5//efficiency of dielectric heating process

+Pi=P/e//power input required in Watts

+Ko=8.854*(10^-12)//absolute permittivity

+K=5//relative permittivity

+A=0.5*0.2//area in m

+i=0.02

+C=Ko*K*A/i//capacitance of parallel plate capacitor in F

+Xc=1/(2*%pi*f*C)//capacitive reactance in ohms

+cosx=0.05

+tanx=19.97

+R=Xc*tanx//resistance

+V=sqrt(Pi*R)//voltage in volts

+Ic=V/Xc//current through the board in Amps

+printf('Thus the power required is %2.1f Watts\n',Pi)

+printf('And Voltage across the board is %3.2f volts\n',V)

+printf('And the current through the board is %2.3f Amps',Ic)