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authorpriyanka2015-06-24 15:03:17 +0530
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+//Finding current
+//Example 15.20(pg. 405)
+clc
+clear
+//Let current in XA=I, in XY=I1, in AY=I-40, in YB=I-40+I1-60, in BX=I+I1-150.
+//By Kirchhoff's second law, in circuit XAYA I-I1=20
+// and in circuit XAYBX 25I+15I1=1950
+I1=(1950-500)/(15+25)//in Amperes
+printf('Thus the current in branch XY is I1=%2.2f Amps',I1)