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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+
+//Inputs
+//The Values in the program are as follows:
+//Temperature in Celcius converted to Kelvin(by adding 273)
+//Pressure in bar converted to kPa (by multiplying 100)
+//Volume in m^3
+//Value of R,Cp and Cv in kJ/kg K
+T1=25+273;
+T2=145+273;
+m=2;
+R=267;
+G=1.4;
+Cv=R/(G-1);
+printf('The value of Cv: %3.1f J/kg K',Cv);
+printf('\n');
+Cp=G*Cv;
+printf('The value of Cp: %3.1f J/kg K',Cp);
+printf('\n');
+U=m*Cv*(T2-T1)*(1/1000);
+printf('The change in Internal Energy: %3.1f kJ',U);
+printf('\n');
+H=m*Cp*(T2-T1)*(1/1000);
+printf('The Heat Transfer: %3.1f kJ',H);
+printf('\n');