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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+
+//Inputs
+//The Values in the program are as follows:
+//Temperature in Celcius converted to Kelvin(by adding 273)
+//Pressure in bar converted to kPa (by multiplying 100)
+//Volume in m^3
+//Value of R,Cp and Cv in kJ/kg K
+m=1;
+P2=25;
+P1=1;
+pV=260;
+T1=17+273;
+T2=T1;
+V1=(pV*T1)/(P1*100000);
+printf('As process is Isothermal, Initial and Final Temperatures are same \n');
+printf('The Final Temperature: %3.0f K',T1);
+printf('\n');
+V2=(pV*T2)/(P2*100000);
+printf('The Final Volume: %3.5f m^3',V2);
+printf('\n');
+CR=P2/P1;
+printf('The Compression Ratio: %3.0f ',CR);
+printf('\n');
+printf('Change in Enthalpy is zero as it is Isothermal process \n');
+W=P1*100*V1*(log(P1/P2));
+printf('Work Done is: %3.1f kJ',W);
+printf('\n');