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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2300/CH23/EX23.31.3/Ex23_3.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '2300/CH23/EX23.31.3/Ex23_3.sce')
| -rwxr-xr-x | 2300/CH23/EX23.31.3/Ex23_3.sce | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/2300/CH23/EX23.31.3/Ex23_3.sce b/2300/CH23/EX23.31.3/Ex23_3.sce new file mode 100755 index 000000000..601dc940a --- /dev/null +++ b/2300/CH23/EX23.31.3/Ex23_3.sce @@ -0,0 +1,13 @@ +//scilab 5.4.1
+//Windows 7 operating system
+//chapter 23 Lasers,Fibre Optics,and Holography
+clc
+clear
+//To obtain interference fringes of good visibility the path difference for the central fringe must be an integral multiple of each of the 2 wavelengths.
+//2*d=(n1*y1)=(n2*y2)where y1 & y2 are 2 wave-lengths and d=path difference and n1 and n2 are 2 integers
+//(2*d)*((1/y2)-(1/y1))=(n2-n1)=m where m is another integer
+//Now m=(-2*d*Y)/(y^2)=(2*d*V)/(v*y)=(2*d*V)/c=(2*d)/Lc
+Lc=600//Lc=coherence length in km
+d=(Lc/2)//d=minimum difference between the 2 arms of the Michelson interferometer
+disp("km",d,"The minimum difference between the two arms of the Michelson interferometer is=")
+
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