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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 6.12// emf
+clc;
+clear;
+close;
+format('v',7)
+disp("part (a) generator ")
+kva=4;//kVA
+v=110;//volts
+re=3;//syncronous reacrance in ohms
+ip=((kva*10^3)/(sqrt(3)*v));//phase current in Amperes
+ep=v/(sqrt(3));//phase voltage in volts
+e1=ep+%i*(ip*3);//line voltage in volts
+e11=sqrt((real(e1)^2)+imag(e1)^2);//line voltage per phase in volts
+pf=0.8;//power factor
+e12=(sqrt((real(e1)*pf)^2+(((imag(e1)*sqrt(1-pf^2))+imag(e1)))^2));//
+e13=(sqrt((real(e1)*pf)^2+(((imag(e1)*sqrt(1-pf^2))-imag(e1)))^2));//
+disp(e11,"emf when the armature current is full load unit pf is,(V)=")
+disp(e12,"emf when the armature current is full load 0.8 pf (lag) is,(V)=")
+disp(e13,"emf when the armature current is full load 0.8 pf (lead) is,(V)=")
+disp("part (b) motor")
+kva=4;//kVa
+v=110;//volts
+re=3;//syncronous reacrance in ohms
+ip=((kva*10^3)/(sqrt(3)*v));//phase current in Amperes
+ep=v/(sqrt(3));//phase voltage in volts
+e1=ep-%i*(ip*3);//line voltage in volts
+e11=sqrt((real(e1)^2)+imag(e1)^2);//line voltage per phase in volts
+pf=0.8;//power factor
+e12=(sqrt((real(e1)*pf)^2+(((imag(e1)*sqrt(1-pf^2))-imag(e1)))^2));//
+e13=(sqrt((real(e1)*pf)^2+(((imag(e1)*sqrt(1-pf^2))+imag(e1)))^2));//
+disp(e11,"emf when the armature current is full load unit pf is,(V)=")
+disp(e12,"emf when the armature current is full load 0.8 pf (lag) is,(V)=")
+disp(e13,"emf when the armature current is full load 0.8 pf (lead) is,(V)=")