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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2273/CH4/EX4.14 | |
download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip |
initial commit / add all books
Diffstat (limited to '2273/CH4/EX4.14')
-rwxr-xr-x | 2273/CH4/EX4.14/ex4_14.sce | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/2273/CH4/EX4.14/ex4_14.sce b/2273/CH4/EX4.14/ex4_14.sce new file mode 100755 index 000000000..ec4b8a725 --- /dev/null +++ b/2273/CH4/EX4.14/ex4_14.sce @@ -0,0 +1,13 @@ +//Find the capacitance of 2 wire 1 phase line
+clear;
+clc;
+//soltion
+//given
+r=0.25;//cm//radius of the conductor
+d=150;//cm//spacing
+L=50000;//m//length of the line
+h=700//cm//height of conductor above earth
+Eo=8.854*10^-12//permitivity of the air
+C=%pi*Eo*L/(log(120/(sqrt(1+(d^2/(2*h)^2))*r)));
+C_=C*10^6;
+printf("Capacitance of 50km line= %.3fµF",C_);
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