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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2273/CH2/EX2.1/ex2_1.sce | |
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initial commit / add all books
Diffstat (limited to '2273/CH2/EX2.1/ex2_1.sce')
-rwxr-xr-x | 2273/CH2/EX2.1/ex2_1.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/2273/CH2/EX2.1/ex2_1.sce b/2273/CH2/EX2.1/ex2_1.sce new file mode 100755 index 000000000..a9f1513a2 --- /dev/null +++ b/2273/CH2/EX2.1/ex2_1.sce @@ -0,0 +1,17 @@ +//Calculate the most economical cross sectional area
+clear;
+clc;
+//soltion
+//given
+id=0.15;//interest & depreciation charges
+i=260;//ampere//max current
+d=0.173;//ohm//resistance of conductor
+cst=.03;//rs// cost of energy per unit
+t=(365*24)/2;//time of energy loss
+printf("Annual cost of 2 core feeder cable is Rs(90a+10)per meter\n");
+P3=(2*i^2*d*t*cst)/1000//kWh//annual cost of energy loss
+printf("Energy loss per annum= P3/a= %f/a \n",P3);
+P2=90*1000*id;//energy lost per annum
+printf("Capital cost= P2*a= %d*a \n", P2);
+a=sqrt(P3/P2);
+printf("Economic cross section of conductor is= √(P3/P2)= %f square cm",a);
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