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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2240/CH20/EX19.11 | |
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initial commit / add all books
Diffstat (limited to '2240/CH20/EX19.11')
| -rwxr-xr-x | 2240/CH20/EX19.11/EX19_11.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/2240/CH20/EX19.11/EX19_11.sce b/2240/CH20/EX19.11/EX19_11.sce new file mode 100755 index 000000000..0e9fd74ac --- /dev/null +++ b/2240/CH20/EX19.11/EX19_11.sce @@ -0,0 +1,18 @@ +// Grob's Basic Electronics 11e
+// Chapter No. 19
+// Example No. 19_11
+clc; clear;
+// A power transformer has 100 turns for Np and 600 turns for Ns. What is the turns ratio? How much is the secondary voltage Vs if the primary voltage Vp is 120 V?
+
+// Given data
+
+np = 100; // Turns in primary coil=100
+ns = 600; // Turns in secondary coil=600
+vp = 120; // Primary voltage=120 Volts
+
+Tr = np/ns;
+disp (Tr,'The Turns Ratio is')
+disp ('OR 1:6')
+
+vs = vp*(ns/np);
+disp (vs,'The Secondary Voltage in Volts')
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