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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// scilab Code Exa 18.43 Francis turbine 250 rpm
+
+NS=0.4; //specific speed
+N=250; // Speed in RPM
+H=75; // net head in m
+beta3=25; // exit angle of the runner blades
+n_o=0.81; // overall efficiency
+g=9.81; // gravitational acceleration in m/s2
+rho=1000; // density in kg/m3
+// part(a)
+u2=0.6*sqrt(2*g*H);
+cr2=0.21*sqrt(2*g*H);
+omega=%pi*2*N/60;
+Q=(NS^2)*(H^(3/2))/((0.1804^2)*(omega^2));
+disp("m3/s",Q,"(a)the discharge rate for the turbine is")
+// part(b)
+d2=u2*60/(%pi*N);
+disp("m",d2,"(b)outer diameter of the runner blade ring is")
+cr3=cr2;
+cx3=cr3;
+//Euler work,w_ET=u2*c_theta2
+c_theta2=((g*H)-(0.5*(cx3^2)))/u2;
+u3=cx3/(tand(beta3));
+d3=u3*60/(%pi*N);
+disp("m",d3,"and inner diameter of the runner blade ring is")
+// part(c)
+alpha2=atand(cr2/c_theta2);
+disp("degree",alpha2,"(c)the inlet guide vane exit angle is")
+beta2=atand(cr2/(c_theta2-u2));
+disp("degree",beta2,"and inlet angle of the runner blades is beta2= ")
+// part(d)
+n_h=(u2*c_theta2)/(g*H);
+disp("%",n_h*1e2,"(d)the hydraulic efficiency is")
+// part(e)
+P=n_o*rho*g*Q*H;
+disp("MW",P*1e-6,"(e)the output power is")
+disp("comment: the calculation for c_theta2 is done wrongly in the book. hence the values of alpha2,beta2, n_h differs from the book.")