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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 5, Problem 3
+clc
+f1=260*10^6 //frequency in hertz
+f2=100*10^6 //frequency in hertz
+A=40 //minimum attenuation in dB
+
+//calculation
+fr=f1/f2
+n=A/(20*log10(fr))
+
+printf("Number of arms = %f\n i.e 5 arms",n)