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+clc

+clear

+//Input data

+af=25//Air fuel ratio

+CV=10000//Calorific value in kcal/kg

+cv=[0.17,0.00004]//Cv=0.17+0.00004T where Cv is Specific heat at constant volume and T is the temperature in K

+r=14//Compression ratio

+T2=800+273//Temperature at the end of compression in K

+R=29//Characteristic gas constant in mkg/kg/degree C

+J=427//Mechanical equivalent of heat in kg.m/kcal

+

+//Calculations

+CVm=(CV/(af+1))//Calorific value of mixture in kcal/kg

+cpv=(R/J)//Difference in mean specific heats in kcal/kg mol.K

+a=(cv(2)/2)//For solving T3

+b=cpv+cv(1)//For solving T3

+c=(-T2*(cpv+cv(1)))-((cv(2)/2)*T2^2)-CVm//Foe solving T3

+T3=(-b+sqrt(b^2-(4*a*c)))/(2*a)//Soving for T3 in K

+s=((T3/T2)/(r-1))*100//Percentage of the stroke

+

+//Output

+printf('The percentage of the stroke at which the combustion will be complete is %3.2f percent',s)