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+clc

+clear

+//Input data

+p1=1//Pressure at intake in kg/cm^2

+T1=100+273//Intake temperature in K

+r=10//Compression ratio

+p3=70//Maximum pressure of the cycle in kg/cm^2

+q=400//Amount of heat added in kcal/kg of air

+Cp=0.24//Specific heat at constant pressure in kJ/kg.K

+Cv=0.17//Specific heat at constant volume in kJ/kg.K

+g=1.41//Ratio of specific heats

+

+//Calculations

+T2=(T1*r^(g-1))//Temperature at the end of compression in K

+p2=(p1*r^g)//Pressure at the end of compression in kg/cm^2

+T3=T2*(p3/p2)//Temperature at the end of constant volume heat addition in K

+qv=(Cv*(T3-T2))//Heat added at constant volume in kcal/kg

+qp=(q-qv)//Heat added at constant pressure in kcal/kg

+T4=(qp/Cp)+T3//Temperature at the end of constant pressure heat supply in K

+k=(T4/T3)//Cut off ratio

+T5=T4/(r/k)^(g-1)//Temperature at the end of expansion in K

+qv2=Cv*(T5-T1)//Heat added at constant volume in kcal/kg

+W=q-qv2//Workdone in kcal/kg of air

+na=(W/q)*100//Air standard efficiency in percent

+

+//Output

+printf('The temperature at the five cardinal points of the cycle are : \n point 1 is %3.0f K \n point 2 is %3.0f K \n point 3 is %3.0f K \n point 4 is %3.0f K \n point 5 is %3.0f K \n\n The air standard efficiency of the engine is %3.1f percent',T1,T2,T3,T4,T5,na)