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+// Exa 8.2

+clc;

+clear;

+close;

+// Given data

+CH4 = 77;// in %

+C2H6 = 22.5;//in %

+H1 = 40.08;// heat liberated by CH4 in MJ/nm^3

+H2 = 69.52;// heat liberated by C2H6 in MJ/nm^3

+HCV = (CH4*H1+C2H6*H2)/100;// Higher calorific value in kJ/kg

+disp(HCV,"The higher calorific value in MJ/nm^3")

+V1= CH4*2/100;// volume of water due to combustion of CH4 in m^3

+V2= C2H6*3/100;// volume of water due to combustion of C2H6 in m^3

+V= V1+V2;// total volume in m^3

+ms= 18/22.41;// in kg

+LCV= HCV-ms*V*2.242;// in MJ/nm^3

+disp(LCV,"The lower calorific value in MJ/nm^3")

+disp("The word nm^3 means that cubic metre at normal temperature and pressure")

+

+// Note: The calculated value in the book is not accurate