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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 6.28
+clc;
+clear;
+close;
+// Given data
+h_f1 = 670;// in kJ/kg
+h_fg1 = 2085;// in kJ/kg
+h_f2 = 475;// in kJ/kg
+h_fg2 = 2221;// in kJ/kg
+P2 = 6*10^2;// in kJ/kg
+P1 = 1.6*10^2;// in kJ/kg
+n = 1.1;
+x1 = 0.9;
+V1 = 0.3159;// in m^3
+V2 = 1.092;// in m^3
+H_wet = h_f1 + (x1*h_fg1);// in kJ/kg
+V_wet1 = x1*V1;// in m^3
+V_wet2 = V_wet1*(P2/P1)^(1/n);// in m^3
+x2 = V_wet2/V2;
+H_wet2 = h_f2 + (x2*h_fg2);// in kJ/kg
+U2= H_wet2-H_wet+P2*V_wet1-P1*V_wet2;// in kJ/kg
+W= (P2*V_wet1-P1*V_wet2)/(n-1);// in kJ/kg
+Q= U2+W;// in kJ/kg
+disp(Q,"Heat recieved by steam in kJ/kg is");