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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Example 4.2
+clc;
+clear;
+close;
+// Given data
+T1= 800+273;// in K
+T2= 400+273;// in K
+T3= 179+273;// in K
+T0= 25+273;// in K
+Q= 2018.4;// heat taken by water in kJ/kg
+// Formula mCp*(T1-T2)= Q
+mCp= Q/(T1-T2);
+delta_Qgas= mCp*integrate('1/T','T',T1,T2);// in kJ/K
+delta_Qwater= Q/T3;// in kJ/K
+delta_Qnet= delta_Qwater+delta_Qgas;// in kJ/K
+disp(delta_Qnet,"Net entropy changes in kJ/K is : ")
+E1= T0*abs(delta_Qgas);// Original unavailable energy in kJ
+E2= T0*delta_Qwater;//unavailable energy after heat transfer in kJ
+E= E2-E1;// in increase in unavailable energy in kJ
+disp(E,"The increase in unavailable energy in kJ is : ")
+
+// Note: There is some difference in the value of increase in unavailable energy because in the book the value of change of entropy of the gas is not correct.