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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 3.5
+clc;
+clear;
+close;
+// Given data
+P1 = 1.1;// in MN/m^2
+P1 = P1 * 10^6;// in N/m^2
+V1 = 1.5;// in m^3
+V2 = 7.5;// in m^3
+P2 = (P1*V1)/V2;// in kN/m^2
+P2 = P2 * 10^-6;// in MN/m^2
+P2 = P2 * 10^3;// in kN/m^2
+disp(P2,"The final pressure in kN/m^2 is");
+W = P1*V1*log(V2/V1);// in J
+W = W * 10^-3;// in kJ
+disp(W,"The work done in kJ is");
+
+// Note : There is an error in calculation to find the value of Work Done. So the answer in the book is wrong