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authorpriyanka2015-06-24 15:03:17 +0530
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+// Exa 3.18
+clc;
+clear;
+close;
+// Given data
+C_P = 1.005;// in kJ/kg-K
+C_V = 0.718;// in kJ/kg-K
+R = C_P - C_V;// in kJ/kg-K
+R= R*10^3;//in J/kg-K
+P1 = 3*10^5;//in N/m^2
+V1 = 1.5;// m^3
+T1 = 15;// in degree C
+T1 = T1 +273;// in K
+m1 = (P1*V1)/(R* T1);// in kg
+m2 = m1+2;//final mass of air in kg
+P2 = P1 * (m2/m1);// in kN/m^2
+T1 = T1 - 273;// in degree C
+T2 = 0;// in degree C
+m = 1;// in kg
+del_U = m * C_P * (T1-T2);// kJ
+disp(del_U,"Total enthapy of air in kJ is");