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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 3.17
+clc;
+clear;
+close;
+// Given data
+C_V = 2.174;// in kJ/kg-K
+R = 0.5196;// in kJ/kg-K
+C_P = C_V+R;// in kJ/kg-K
+V2 = 1;// in m^3
+V1 = 8;// in m^3
+P1 = 0.7;// in bar
+P2 = 7;// in bar
+del_U = C_P * (log(V2/V1)) + C_V * (log(P2/P1));// in kJ/kg-K
+m = 0.9;// in kg
+del_U = m * del_U;// in kJ/K
+disp(del_U,"Change in entropy in kJ/K is");
+disp("It is a loss of entropy")