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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+//initialisation of variables
+a=39.7//mole air
+b=15.85 //mole air
+c=7.94 //mole air
+d=3.76 //mole air
+AF=(b+3.76*b)/a//mole air /lbm fuel
+AF1=1.233 //moles air /lbm fuel
+//CALCULATIONS
+Air=AF/AF1*100//percent
+//RESULTS
+printf('the actual air fuel ratio on a mole basic=% f percent',Air)