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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Exa 2.33
+clc;
+clear;
+close;
+format('v',7);
+
+//Given Data :
+p1=10^5;//Pa
+p2=5*10^5;//Pa
+T1=25+273;//K
+V1=1.8;//m^3/Kg
+V2=p1/p2*V1;//m^3/Kg
+W=-p1*V1*log(p2/p1);//J/kg
+W=W/1000;//KJ/Kg
+disp(W,"Workdone in KJ : ");
+deltaU=0;//As in a isothermal process T2-T1 =0
+disp(deltaU,"Change in internal energy in KJ : ");
+Q=-W;//KJ/Kg(As in a isothermal process T2-T1 =0 )
+disp(Q,"Heat Transfered in KJ/Kg : ");