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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//To find speed, direction and torque
+clc
+//Given:
+TA=14, TC=100
+r=98/41 //TE/TD
+PA=1.85*1000 //W
+NA=1200 //rpm
+//Solution:
+//Refer Fig. 13.28 and Table 13.23
+//Calculating the number of teeth on wheel B
+TB=(TC-TA)/2
+//Calculating the values of x and y
+//From the fourth row of the table, -y+x*(TA/TC) = 0, or x*(TA/TC)-y = 0 .....(i)
+//Also, -x-y = 1200, or x+y = -1200 .....(ii)
+A=[TA/TC -1; 1 1]
+B=[0; -1200]
+V=A \ B
+x=V(1)
+y=V(2)
+//Calculating the speed of gear E
+NE=round(-y+x*(TA/TB)*(1/r)) //rpm
+//Fixing torque required at C:
+//Calculating the torque on A
+Ta=PA*60/(2*%pi*NA) //Torque on A, N-m
+//Calculating the torque on E
+Te=PA*60/(2*%pi*NE) //Torque on E
+//Calculating the fixing torque required at C
+Tc=Te-Ta //Fixing torque at C, N-m
+//Results:
+printf("\n\n Speed and direction of rotation of gear E, NE = %d rpm, anticlockwise.\n\n",NE)
+printf(" Fixing torque required at C = %.1f N-m.\n\n",Tc) \ No newline at end of file