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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//To find power and shaft speed
+clc
+//Given:
+funcprot(0)
+beta=30/2 //degrees
+alpha=750*10^-6 //mm^2
+mu=0.12
+rho=1.2*1000 //kg/m^3
+sigma=7*10^6 //N/m^2
+d=300/1000 //m
+N=1500 //rpm
+//Solution:
+//Power transmitted:
+//Calculating the velocity of the belt
+v=%pi*d*N/60 //m/s
+//Calculating the mass of the belt per metre length
+l=1 //m
+m=alpha*l*rho //kg/m
+//Calculating the centrifugal tension
+TC=m*v^2 //N
+//Calculating the maximum tension in the belt
+T=sigma*alpha //N
+//Calculating the tension in the tight side of the belt
+T1=T-TC //N
+//Calculating the tension in the slack side of the belt
+theta=%pi //Angle of contact, radians
+T2=T1/exp(mu*theta*(1/sind(beta))) //N
+//Calculating the power transmitted
+P=(T1-T2)*v*2/1000 //kW
+//Shaft speed:
+//Calculating the belt speed for maximum power transmitted
+v1=sqrt(T/(3*m)) //m/s
+//Calculating the shaft speed for maximum power transmitted
+N1=v1*60/(%pi*d) //rpm
+//Results:
+printf("\n\n Power transmitted, P = %.3f kW.\n\n",P)
+printf(" Shaft speed at which the power transmitted would be maximum, N1 = %d rpm.\n\n",N1) \ No newline at end of file