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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//To find diameter and number of collars
+clc
+//Given:
+d2=300/1000,r2=d2/2 //m
+W=200*1000 //N
+N=75 //rpm
+mu=0.05
+p=0.3 //N/mm^2
+P=16*1000 //W
+//Solution:
+//Calculating the angular velocity of the shaft
+omega=2*%pi*N/60 //rad/s
+//Calculating the total frictional torque transmitted
+T=P/omega //N-m
+//Calculating the external diameter of the collar
+//We have, T=2/3*mu*W*(r1^3-r2^3)/(r1^2-r2^2), or (2*mu*W)*r1^2-(3*T-2*mu*W*r2)*r1+(2*mu*W*r2^2-3*T*r2)=0
+A=2*mu*W, B=-(3*T-2*mu*W*r2), C=2*mu*W*r2^2-3*T*r2
+r1=(-B+sqrt(B^2-4*A*C))/(2*A)*1000 //mm
+d1=2*r1 //mm
+//Calculating the number of collars
+n=W/(p*%pi*(r1^2-(r2*1000)^2))
+//Results:
+printf("\n\n External diameter of the collar, d1 = %d mm.\n",d1)
+printf(" Number of collars, n = %d.\n\n",n+1) \ No newline at end of file